Forum JEE Advanced (IIT) 12th Pass(Dropper) If a,b satisfy equation sin2a=…
Rohit Mittal
Answers (1)
pooja singh
sin2a=cos2b can be written as
sin2a=sin(pi/2-2b)
2a=pi/2-2b
a=pi/4-b
2/pi(a-b-pi/4)=2/pi(pi/4-2b-pi/4)
=-4b/pi
1 year ago
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